-16x^2+16+672=0

Solution for -16x^2+16+672=0 equation:

-16x^2+16+672=0

We add all the numbers together, and all the variables

-16x^2+688=0

a = -16; b = 0; c = +688;
Δ = b2-4ac
Δ = 02-4·(-16)·688
Δ = 44032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{44032}=\sqrt{1024*43}=\sqrt{1024}*\sqrt{43}=32\sqrt{43}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{43}}{2*-16}=\frac{0-32\sqrt{43}}{-32}
=-\frac{32\sqrt{43}}{-32}
=-\frac{\sqrt{43}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{43}}{2*-16}=\frac{0+32\sqrt{43}}{-32}
=\frac{32\sqrt{43}}{-32}
=\frac{\sqrt{43}}{-1}
$